What is the x and y intercept of the parabola y=x^2-6x+10 and ow do you graph the equation

The x - intercept is where y = 0 on the graph and the y - intercept is where x = 0 on the graph. When X=0, all the terms, except for the constant are equal to zero, thus the y - intercept is the constant. y=10 when x=0. Use the quadratic formula to find the x value where y=0.

x = (-b + or - sqrt (b^2 - 4ac)) / 2a

y=ax^2 + bx + c

The answer for the x - int is imaginary. This happens because 10 is the parabola's minimum value and it never touches the x - axis. y-int is 10