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16 February, 04:18

Let cos (-θ) = - 3/5

and tanθ>0.

What is the value of sin (-θ) ?

A. - 3/5

B. 4/5

C. - 4/5

D. 4/3

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Answers (1)
  1. 16 February, 06:56
    0
    Cos (-x) = cos (x) = - 3/5=a/h

    sin (-x) = - sin (x) = - o/h=o/5

    we know 3^2+4^2=5^2 so

    sin (-x) = 4/5 its B
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