X^2+y^2+3x=0 Find the x and y intercepts

Hello,

x=0==> y=0

y=0==> x²+3x=0==>x (x+3) = 0==>x=0 or x=-3

x²+y²+3x=0

==> (x²+2*3/2x+9/4) + y²=9/4

==> (x+3/2) ²+y² = (3/2) ²

is the equation of the circle of center (-3/2,0) and radius 3/2 where the tangent to the circle at (0,0) is the axis 0y.