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17 June, 19:49

Perform the indicated operations and write the result in the form of a + bi

(3 - 2i) (4 + 3i)

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  1. 17 June, 23:15
    0
    Remember:

    i=√-1

    i² = (√-1) (√-1) = - 1

    (3-2i) (4+3i) =

    = (3*4) + (3*3i) + (-2i*4) + (-2i*3i)

    =12+9i-8i-6i²

    =12 + (9i-8i) - (6*-1)

    =12+i+6

    =18+i

    Answer: (3-2i) (4+.3i) = (18+i)
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