How do you do 5ln x = 35 ... ?

That's going to depend a lot on what you want to "do" to it.

I'm going to assume that you want to find a number for 'x' that makes

the whole equation a true statement. Here's how I would do it:

5 ln (x) = 35

Divide each side by 5: ln (x) = 35/5

ln (x) = 7

Raise 'e' to the power of each side: e^[ ln (x) ] = e⁷

But e^[ ln (x) ] is just 'x'. So x = e⁷ = 1,096.633 ... (rounded)

That's the only number you can write in place of 'x'

and make the original equation true.