P Casey is reading a book for a book report. At 3:30 P. M., he started reading where he had left off the day before. At 5:30 P. M. he was on page 160. At 8:00 P. M. he was on page 280. If reading the book is modeled by a linear function, what page did Casey start on at 3:30 P. M.?

Question

Mathematics

Tristen Oconnell

18 November, 01:07

P Casey is reading a book for a book report. At 3:30 P. M., he started reading where he had left off the day before. At 5:30 P. M. he was on page 160. At 8:00 P. M. he was on page 280. If reading the book is modeled by a linear function, what page did Casey start on at 3:30 P. M.?

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Answers (2)

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King Bridges · Answer 1

Given:

3:30 - 5:30 = page 160

5:30 - 8:00 = page 280

280 - 160 = 120

8:00 - 5:30 = 2.5 hours or 5 half hours

120 / 5 half hours = 24 pages every half hour or 30 minutes

3:30 - 5:30 = 2 hours or 4 half hours

24 * 4 = 96 pages

160 - 96 = 64

P Casey was on page 64 at 3:30 p. m.

Ivy · Answer 2

If you would like to know the page that Casey start on at 3:30 P. M., you can calculate this using the following steps:

8:00 P. M. - 5:30 P. M. = 2:30

280 - 160 = 120 pages

5:30 P. M. - 3:30 P. M. = 2:00

2:30 = 150 minutes ... 120 pages

2:00 = 120 minutes ... x pages = ?

150 * x = 120 * 120

x = 120 * 120 / 150

x = 96 pages

160 pages - 96 pages = 64

Casey started on page 64.