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12 October, 12:58

Find the roots of x^2-4x+6=0

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  1. 12 October, 16:25
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    x² - 4x + 6 = 0

    x² - 2x = - 6 + ( - 2) ²

    x² - 2x = - 6 + 4

    (x - 2) ² = - 2

    x - 2 = ± 2i

    Answer: x = 2 ± 2i-no real root [imaginary solutions only]
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