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18 April, 21:32

After a devastating winter, when thousands of fish died, an environmental scientist has replenished the trout stock in a fishing pond. He started with 5,000 baby trout and has finished a count to find that, in 4 years, the population is estimated to be 8,500. Assuming an exponential growth pattern, what is the annual growth rate (rounded to the nearest tenth of a percent) of the new trout population?

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  1. 19 April, 00:31
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    The formula for an exponential growth rate is in the form of:

    P = Po e^ (r t)

    Where,

    P = final population after how many years = 8 500

    Po = the initial population = 5 000

    r = the growth rate = unknown (the variable we have to find for)

    t = time in years = 4 years

    Rewriting the equation in the form to find for r:

    P / Po = e^ (r t)

    ln (P / Po) = r t

    r = ln (P / Po) / t

    r = ln (8500/5000) / 4

    r = 0.1327 / year

    Therefore the growth rate is about 13.27% per year.
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