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13 July, 19:10

What is c in (c+3) - 2c - (1-3c) = 2

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  1. 13 July, 19:26
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    Simplifying (c + 3) + - 2c + - 1 (1 + - 3c) = 2 Reorder the terms: (3 + c) + - 2c + - 1 (1 + - 3c) = 2 Remove parenthesis around (3 + c) 3 + c + - 2c + - 1 (1 + - 3c) = 2 3 + c + - 2c + (1 * - 1 + - 3c * - 1) = 2 3 + c + - 2c + (-1 + 3c) = 2 Reorder the terms: 3 + - 1 + c + - 2c + 3c = 2 Combine like terms: 3 + - 1 = 2 2 + c + - 2c + 3c = 2 Combine like terms: c + - 2c = - 1c 2 + - 1c + 3c = 2 Combine like terms: - 1c + 3c = 2c 2 + 2c = 2 Add '-2' to each side of the equation. 2 + - 2 + 2c = 2 + - 2 Combine like terms: 2 + - 2 = 0 0 + 2c = 2 + - 2 2c = 2 + - 2 Combine like terms: 2 + - 2 = 0 2c = 0 Solving 2c = 0 Solving for variable 'c'. Move all terms containing c to the left, all other terms to the right. Divide each side by '2'. c = 0 Simplifying answer c = 0
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