Ask Question
5 March, 16:04

Find the domain of f for f (x) = the square root of 2x+7

+5
Answers (1)
  1. 5 March, 17:11
    0
    Set up the equation to solve for xx. 2x+7≥0 2x+7≥0 Since 77 does not contain the variable to solve for, move it to the right side of the inequality by subtracting 77 from both sides. 2x≥-7 2x≥-7 Divide each term by 2 and simplify.

    Divide each term in 2x≥-7 2x≥-7 by 22. 2x 2 ≥ - 72 2x 2 ≥ - 72 Reduce the expression by cancelling the common factors. Tap for fewer steps ... Cancel the common factor. 2x 2 ≥ - 72 2x 2 ≥ - 72 Divide xx by 11 to get xx. x≥ - 72 x≥ - 72 x≥ - 72 Find the set of inequalities that expresses where xx is defined. 2x+7≥0 2x+7≥0 The domain is all values of xx that make the expression defined. [ - 72,∞) [ - 72,∞) {x ∣∣∣ x≥ - 72 }
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Find the domain of f for f (x) = the square root of 2x+7 ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers