One integer is 5 more than another. Their product is 126. Find the integers.

A * b = 126

a = b + 5

b (b + 5) = 126

b^2 + 5b - 126 = 0

(b - 9) (b + 14) = 0

b - 9 = 0

b = 9

b + 14 = 0

b = - 14 ... this is extraneous solution ... it is not correct

a = b + 5

a = 9 + 5

a = 14

ur 2 integers are 9 and 14