Find the equation of the line that passes through (6,0) and (-3,-3)

Slope = (y2 - y1) / (x2 - x1)

slope = (-3 - 0) / (-3 - 6)

slope = - 3/-9

slope = 1/3

y = mx + b

0 = 1/3 (6) + b

0 = 2 + b

so

b = - 2

Equation:

y = mx + b

y = 1/3x - 2

answer:

equation of line that passes through (6,0) and (-3,-3):

y = 1/3x - 2