Debbieis one year older than dave. James is twice as old as dave. Joelle is twice as old as debbie. Altogether their ages total 33. Find each persons age. (let x = daves age)

Dave is 5, Debbie is 6, Joelle is 12, and James is 10

X = dave's age

d = debbie's age

j = joelle's age

x + d + j = 33

d = x + 1

j = 2d ... j = 2 (x + 1)

x + (x + 1) + 2 (x + 1) = 33

x + x + 1 + 2x + 2 = 33

4x + 3 = 33

4x = 33 - 3

4x = 30

x = 30/4

x = 7.5 < = = = dave is 7.5 (or 7 1/2) years old

d = x + 1

d = 7.5 + 1

d = 8.5 < = = = debbie is 8.5 (or 8 1/2) years old

j = 2 (x + 1)

j = 2 (7.5 + 1)

j = 2 (8.5)

j = 17 < = = = joelle is 17 years old