Find the smallest zero for the function h (x) = 4x^2-8x-60.

Is that the answer because it wont let me add both answers it will let me add only one

H (x) = 4x² - 8x - 60

0 = 4x² - 8x - 60

0 = 4 (x²) - 4 (2x) - 4 (15)

0 = 4 (x² - 2x - 15)

4 4

0 = x² - 2x - 15

0 = x² - 5x + 3x - 15

0 = x (x) - x (5) + 3 (x) - 3 (5)

0 = x (x - 5) + 3 (x - 5)

0 = (x + 3) (x - 5)

0 = x + 3 or 0 = x - 5

- 3 - 3 + 5 + 5

3 = x or 5 = x