David measured the distance from his house to a soccer field as 3 km. The actual distance from his house to the soccer field is 2.84 km.

Solve for the approximate percent error in David's measurement. Round to the nearest tenth of a percent, if necessary. A. 0.16% B. 5.3% C. 5.6% D. 16%

Question

Shea Vazquez

3 May, 20:45

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Answers (1)

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Karsyn Savage · Answer 1

The percentage error is given by:

(error/actual value) x 100

= [ (3-2.84) / 2.84] x 100

= 5.6%

The answer is C

David measured the distance from his house to a soccer field as 3 km. The actual distance from his house to the soccer field is 2.84 km.Solve for the approximate percent error in David's measurement. Round to the nearest tenth of a percent, if necessary. A. 0.16% B. 5.3% C. 5.6% D. 16%