A ball is thrown from a height of 140 feet with an initial downward velocity of 8 ft/s. The ball's height (in feet) after seconds is given by the following. h = 140 - 8t - 16t^2 How long after the ball is thrown does it hit the ground? Round your answer (s) to the nearest hundredth.

Question

Harper Baldwin

18 July, 08:28

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Answers (1)

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Miya Arroyo · Answer 1

When it hits the ground h (t) = 0 so:-

140 - 8t - 16t^2 = 0

4t^2 + 2t - 35 = 0

t = 2.72 answer