Ask Question
11 January, 16:28

A certain number is 3 more than twice another. If their sum is increased by 8, the result is 41. Find the numbers.

+3
Answers (1)
  1. 11 January, 16:55
    0
    X = 2y + 3

    (x + y) + 8 = 41

    (2y + 3 + y) + 8 = 41

    3y + 11 = 41

    3y = 41 - 11

    3y = 30

    y = 30/3

    y = 10

    x = 2y + 3

    x = 2 (10) + 3

    x = 23

    ur numbers are 10 and 23
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A certain number is 3 more than twice another. If their sum is increased by 8, the result is 41. Find the numbers. ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers