The area of a playground is 336 yd2. The width of the playground is 5 yd longer than its length. Find the length and width of the playground

L=16

W=21

Set up a systems of equations:

x=length

y=width

xy=336

x+5=y

Use substitution to solve:

x (x+5) = 336

x^2+5x=336

Solve using factoring:

x^2+5x-336=0

(x-16) (x+21) = 0

x=16 and x = - 21

Since length can't be negative, l=16

To find width, plug length into the first equation:

(16) y=336

y=21

So ...

L=16

W=21