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4 December, 13:27

A retanglular athletic field has an area of 40x2+190x-50. The width of the field is 8x-2. What is the length of the athletic field?

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  1. 4 December, 15:24
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    Length = Area/Width

    Length = 40x2+190x-50 / 8x - 2

    Length = 10 (4x2+19x-5) / 2 (4x - 1)

    Length = 5 (4x2+19x-5) / (4x - 1)

    Length = 20x2 + 95x - 25 / 4x - 5

    Length = 5x + 25
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