Find the perimeter of a triangle xyz (0,2) (4,-1) (-2,-1)

First find each side of the triangle

XY = √ (4-0) ² + (-1-2) ²

XY = √ (4² + (-3) ²)

XY = √ (16 + 9)

XY = √25

XY = 5

XZ = √ (-2-0) ² + (-1-2) ²

XZ = √ ((-2) ² + (-3) ²)

XZ = √ (4 + 9)

XZ = √13

YZ = √ (4+2) ² + (-1+1) ²

YZ = √ (6² + 0)

YZ = √36

YZ = 6

Find the perimeter

Perimeter = XY + XZ + YZ

Perimeter = 5 + √13 + 6

Perimeter = 11 + √13