Morgan rolls a number cube, twice. If the number 1 shows up at least once, Morgan wins. Otherwise, Jaclyn wins. How much greater is the probability that Morgan will win compared to Jaclyn winning?

A) 1/3 B) 7/18 C) 4/9 D) 2/3

I am assuming from the answer choices that you meant Jaclyn's chances of winning.

There are 6 sides of a dice and it's rolled twice.

6*2=12

So while Morgan has a 2/12 chance (simplified that would be 1/6), Jaclyn has a 10/12 chance of winning (simplified that would be 1/3).

Therefore your answer would be A: 1/3