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4 August, 11:37

Dad is 4 times as old as his son Jim. In 10 years, Dad's age will be 20 years more than twice Jim's age. How old is Jim?

If D = dad's age now and J = Jim's age now, which of the following systems could be used to solve the problem?

a. D = 4J and D + 10 = 2J + 20

b. D = 4J and D + 10 = 2 (4J + 10) + 20

c. D = 4J and D + 10 = 2 (J + 10) + 20

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Answers (1)
  1. 4 August, 13:58
    0
    Let's focus on the "In 10 years" part

    in 10 years

    D will be (D + 10)

    and J will be (J + 10)

    "twice Jim's age" would then be 2 (J + 10)

    and

    "20 years more than" that would be 2 (J + 10) + 20

    so

    the answer with

    D + 10 = 2 (J + 10) + 20

    would be your answer

    that is, C.
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