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18 February, 00:48

3 (2a 5) and 6a+15 Verify informally that the two expressions are equivalent using substitution. (Let a = 4)

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  1. 18 February, 02:18
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    Since a = 4, just plug in 4 every time you see a, and solve normally.

    3 (2a + 5)

    3 (2 • 4 + 5)

    3 (8 + 5)

    3 (12) = 36

    6a + 15

    6 • 4 + 15

    24 + 15 = 39

    Those expressions are not equivalent.
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