Solve 2x2 12x - 14 = 0 by completing the square. 2 (x 6) 2 = 26; x = - 6 square root 13, x = - 6 - square root 132 (x 6) 2 = 20; x = - 6 square root 20, x = - 6 - square root 202 (x 3) 2 = 32; x = 1, x = - 72 (x 3) 2 = 32; x = 13, x = 19

Question

Mathematics

Alberto Wiley

13 March, 01:53

Solve 2x2 12x - 14 = 0 by completing the square. 2 (x 6) 2 = 26; x = - 6 square root 13, x = - 6 - square root 132 (x 6) 2 = 20; x = - 6 square root 20, x = - 6 - square root 202 (x 3) 2 = 32; x = 1, x = - 72 (x 3) 2 = 32; x = 13, x = 19

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Cory Willis · Answer 1

Assuming that the blank space is a plus

2x^2+12x-14=0

isolate x

(2x^2+12x) - 14=0

undistribute 2

2 (x^2+6x) - 14=0

take 1/2 of 6 and square and add negative and positive

2 (x^2+6x+9-9) - 14=0

factor perfect squrae

2 ((x+3) ^2-9) - 14=0

distribute

2 (x+3) ^2-18-14=0

2 (x+3) ^2-32=0

2 (x+3) ^2=32

divide 2

(x+3) ^2=16

sqrt

x+3=+/-4

minus 3

x=+/-4-3

x=-7 or 1

2nd to last option