Ask Question
26 July, 22:39

Ursula and Andre competed against each other in a swimming race. Ursula swam at a rate of 60 meters per minute and Andre swam at a rate of 48 meters per minute. Ursula gave Andre a 1-minute head start.

+2
Answers (1)
  1. 27 July, 01:39
    0
    Given that the two swimmers competed and Ursula's speed is 60 m/min while Andre's speed is 48 m/min. The distance that the Ursula will catch up with Andre will be:

    distance = (relative speed) * (time)

    relative speed=60-48=12 m/min

    the two swimmers met at a distance of:

    12*1

    =12 meters
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Ursula and Andre competed against each other in a swimming race. Ursula swam at a rate of 60 meters per minute and Andre swam at a rate of ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers