49b^2 - 256 = 0

Solve, and show steps if you can!

Note that 49b^2 - 256 = 0 is the difference of two squares. Thus, 49b^2 - 256 = 0 can be re-written as

(7b) ^2 - 16^2 = 0, which factors into (7b+16) (7b-16) = 0.

Solving for b: 7b+16=0 becomes b = - 16/7, and

7b-16=0 becomes b = 16/7.

As expected, this 2nd order equation has 2 solutions.