Ask Question
28 November, 22:38

Mason and Nora decided to swim across the river. Mason began swimming 7.7 seconds earlier than Nora. Mason swam at a speed of 5 feet per second. Nora swam at a speed of 5+1 feet per second. For how many seconds had Mason been swimming at the moment when the two swimmers had swam exactly the same distance?

+3
Answers (1)
  1. 29 November, 01:08
    0
    Let d be distance travelled when they are level, and t = time that nora took to get level with mason for Nora 6 = d/t d = 6t for Mason 5 = d / (t + 35) d = 5 (t + 350 so 6t = 5 (t + 35) solve for t
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Mason and Nora decided to swim across the river. Mason began swimming 7.7 seconds earlier than Nora. Mason swam at a speed of 5 feet per ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers