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25 July, 04:34

The condition proves that ∆ABC and ∆EFG are congruent by the SAS criterion.

If AB ≠ EF, the criterion for congruency is violated. In this situation, angle C angle G.

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  1. 25 July, 06:28
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    If AB ≠ EF, the criterion for congruency is violated. In this situation, angle C angle G are not equal:

    angle C ≠ angle G
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