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29 June, 03:27

The drawing shows two displacements, 3.0 km due north and 4.0 km due east, and the corresponding resultant vector R. What is the angle θ that R makes with respect to due north?

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  1. 29 June, 06:06
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    Tan (theta) = opposite/adjacent = 4/3 = 1.3333 ...

    We can use a calculator:

    ∠ (theta) = tan^ (-1) 1.3333 ... ≈ 53.13° ≈ 53° 7' 48''
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