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18 January, 01:38

Solve the compound inequality below:

3-8r ≤ 3+4r or - 6+4r < 2+4r

No Solution, Ø

r≤0 or - 4>0

r≥0 or - 4<0

All Real Numbers

+5
Answers (1)
  1. 18 January, 02:51
    0
    3 - 8r < = 3 + 4r

    3 - 3 < = 4r + 8r

    0 < = 12r

    0 < = r

    -6 + 4r < 2 + 4r

    4r - 4r < 2 + 6

    0 < 8

    all real numbers

    The "or" statement means combining the sets of solutions.

    combined sets = all real numbers
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