Suppose there are 30 people at a party. do you think any two share the same birthday? let's use the random-number table to simulate the birthdays of the 30 people at the party. ignoring leap year, let's assume that the year has 365 days. number the days, with 1 representing january 1, 2 representing january 2, and so forth, with 365 representing december 31. draw a random sample of 30 days (with replacement). these days represent the birthdays of the people at the party. would you expect any two of the birthdays to be the same?

Question

Mathematics

Sandra Lara

17 February, 02:01

Suppose there are 30 people at a party. do you think any two share the same birthday? let's use the random-number table to simulate the birthdays of the 30 people at the party. ignoring leap year, let's assume that the year has 365 days. number the days, with 1 representing january 1, 2 representing january 2, and so forth, with 365 representing december 31. draw a random sample of 30 days (with replacement). these days represent the birthdays of the people at the party. would you expect any two of the birthdays to be the same?

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Marlene Kemp · Answer 1

In this question, you are asked the probability for any of the 30 person to have the same birthday. To answer this it will be easier to calculate how much the probability for no one has same birthday. Let say the first person birthday is 1. Then the next person birthday should be other than 1, which mean 364 possible days out of 365 days. The next person should be 363 possible days out of 365 days

Then the calculation for 30 people would be:

(365!/365-30!) / (365^ (30) = (365!/335!) / 365^30 = 29.4%

Then the probability of at least two person have same birthday would be: 100%-29.4% = 70.6%