A metallurgist has a alloy with 5% titanium and an alloy with 25% titanium. he needs 100 grams of an alloy with 13% titanium. how much of each alloy should be mixed to attain the 100 grams of alloy with 13% titanium

Question

Samir Costa

1 May, 16:06

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Answers (1)

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Dawson Barr · Answer 1

Setup:

0.1x + 0.3 (100 - x) = 0.24 (100)

0.1x + 30 - 0.3x = 24

-0.2x = - 6

x = 30 g amt of 10% alloy

amt of 30 % alloy = 100 - 30 = 70g