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Factor x 2 + xy - 2x - 2y. (x + 2) (x - y) (x + y) (x - 2) (x - y) (x + 2)

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  1. Today, 15:37
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    X² + xy - 2x - 2y

    The first thing would be to break the polynomial up into pairs.

    (x² + xy) + (-2x - 2y)

    Then you can factor them individually.

    (x² + xy)

    Both numbers have x in common, so you can factor it out and get

    x (x + y)

    Then you factor the other pair,

    (-2x - 2y)

    Both numbers have - 2 in them, so you can factor it out and get

    -2 (x + y)

    Now your two pairs are

    [x (x + y) ] and [-2 (x + y) ]

    Notice that the two terms in parentheses are the same, so you can get rid of one and combine the two outside terms to get a final answer of

    (x - 2) (x + y)
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