Find the center, vertices, and foci of the ellipse with equation 5x2 + 8y2 = 40.

For an ellipse x²/a² + y²/a² = 1

vertices are - a, 0 a, 0 0, b 0, - b focus : √ (a²-b²), 0

center is origin 0,0

given ellipse : divide by 40 on both sides

x² / 8 + y²/5 = 1

So a = √8 = 2√2 b = √5

vertices are - 2√2,0 2√2,0 0,√5 0,-√5

focii = √3, 0 - √3, 0