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16 October, 23:09

Solve for x

log (7x+1) = log (x-2) + 1

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Answers (1)
  1. 17 October, 01:03
    0
    Log (7x+1) - log (x-2) = 1

    log[ (7x+1) / (x-2) ] = 1 or log[ (7x+1) / (x-2) ] = log10 (log10=1)

    it means (7x+1) / (x-2) = 10

    Solving = = = > x=7
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