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7 July, 14:09

A particle moves along a straight line with equation of motion s = f (t), where s is measured in meters and t in seconds. Find the velocity and speed when t = 3.

f (t) = (t ^-1) - t

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  1. 7 July, 14:52
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    F (t) = (t^-1) - t

    Taking derivative:

    f' (t) = d/dt (t^-1) - t) = d/dt (t^-1) - d/dt (t)

    f' (t) = - 1 (t^-2) - 1

    = - t^-2 - 1

    f' (t) = v (t),

    It can be also written as:

    -1/t^2 - 1

    So v (3) = - 1 / (3^2) - 1 = - 1/9 - 1 = - 10/9
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