If her current pattern continues, how many cakes will Karen most likely sell in her 10th week of business? 10, because approximately y = 9 over 10. x + 1 11, because approximately y = 9 over 10. x + 1 8, because approximately y = 1x - 1 12, because approximately y = 1x + 2
+1
Answers (1)
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “If her current pattern continues, how many cakes will Karen most likely sell in her 10th week of business? 10, because approximately y = 9 ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Home » Mathematics » If her current pattern continues, how many cakes will Karen most likely sell in her 10th week of business? 10, because approximately y = 9 over 10. x + 1 11, because approximately y = 9 over 10.