Evaluate 3+√x+19-√2x when x=6. Write the answer as a decimal. Round to the nearest hundredth if necessary.

A.

4.54

B.

11.46

C.

7

D.

-4

Question

Clarissa Campbell

8 February, 03:47

+3

Answers (1)

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Alexander Robbins · Answer 1

3+√x+19-√2x replace x by 6===> 3+√6+19-√2*6 = 3+√6+19-√12

Note that √12 = √2x6 = √2 x √6 = = = >3+√6+19 - (√2) x (√6)

=√6 (1+√2) + 22

Evaluate 3+√x+19-√2x when x=6. Write the answer as a decimal. Round to the nearest hundredth if necessary.A.4.54B.11.46C.7D.-4