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16 November, 01:52

Find four consecutive even integers such that if the sum of the first and the third is multiplied by 5 the result is 12 less than 9 times the fourth

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  1. 16 November, 04:50
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    4 consecutive even integers ... x, x + 2, x + 4, x + 6

    5 (x + x + 4) = 9 (x + 6) - 12

    5 (2x + 4) = 9x + 54 - 12

    10x + 20 = 9x + 42

    10x - 9x = 42 - 20

    x = 22

    x + 2 = 22 + 2 = 24

    x + 4 = 22 + 4 = 26

    x + 6 = 22 + 6 = 28

    so ur numbers are : 22,24,26, and 28
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