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Mathematics
Tomcat
30 December, 19:40
Find the relative extrema of f (x) = 1+8x - 3x^2
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Julia
30 December, 19:57
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F (x) = 1+8x-3x²
1) we have to calculate the first derived
f' (x) = 8-6x
2) we have to equalizate the first derived to "0", and find out the value of "x".
8-6x=0
-6x=-8
x=-8/-6=4/3
3) we have to calculate the second derived
f'' (X) = - 6<0 ⇒ at x=4/3 we have a maximum.
4) we find the value of "y"
f (4/3) = 1+8 (4/3) - 3 (4/3) ²=1 + (32/3) - (48/9) = 57/9
Therefore:
at (4/3, 57/9) have a maximum
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