Ask Question
2 November, 05:07

How to solve (-2-2i) (-4-3i) (7+8i)

+4
Answers (1)
  1. 2 November, 07:13
    0
    Step 1-F. O. I. L.: (-2-2i) (-4-3i)

    8+6i+8i+3i^2

    We know i^2=-1, so ...

    8+14i-3

    5+14i

    Step 2-F. O. I. L. again: (5+14i) (7+8i)

    35+40i+98i+112i^2

    35+138i-112

    -77+138i

    Note: "F. O. I. L." stands for "First, Outer, Inner, Last". In other words, distribute the terms of the first binomial to the other, in that order. So, (5+14i) (7+8i) should be done as follows:

    5*7=56

    5*8i=40i

    14i*7=98i

    14i*8i=112i^2
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “How to solve (-2-2i) (-4-3i) (7+8i) ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers