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2 November, 00:44

How do i simplify: (sin pi/2 - x) / (cos pi/2 - x)

and

sec^2x-1 / secx-1

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Answers (1)
  1. 2 November, 01:04
    0
    tan (x) = sin (x) / cos (x)

    When x = pi/2-x, it's the same thing but you just substitute

    sin (pi/2-x) / cos (pi/2-x) = tan (pi/2-x)

    1/cos (x) = secx

    sec^2 (x-1) / sec (x-1) = sec (x-1) = 1/cos (x-1)
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