Solve, using the substitution method. j + k = 3 j - k = 7

The solution is (8, 1).

The solution is (5, - 2).

There is no solution.

There are an infinite number of solutions.

The solution is (5, - 2)

Take the second equation and rewrite it as j = k + 7

Next plug this into the first equation in place of the j.

SO ... k + 7 + k = 3

2k + 7 = 3

subtract 7 from both sides

2k + 7 - 7 = 3 - 7

2k = - 4

divide both sides by 2

k = - 2

Plug - 2 back in to the equation j = k + 7

j = - 2 + 7

j = 5