How can you express (32 + 56) as a multiple of a sum of whole numbers with no common factor?

To express (32+56) as a multiple sum of whole number we proceed as follows;

32=2*2*2*2*2=2^5

56=2*2*2*5 = (2^3) * 5

Thus;

(32+56)

=2^5+2^3*5

=2^3 (2^2+5)

The answer is:

2^3 (2^2+5)