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16 November, 16:55

What four consecutive odd integers have a sum of 336?

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  1. 16 November, 17:42
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    Call x is the first number.

    The second is x+2

    The third is x+4

    The forth is x+6

    => x + (x+2) + (x+4) + (x+6) = 336

    4x + 12 = 336

    4x = 324

    x = 81

    => the first is 81; the second is 83, the third is 85 and the forth is 87
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