How do you factor 3x^2+7x-6=0 and solve?

Do the factoring method

(3x-2) (x+3)

3x=2 X=-3

x=2/3

if we check

3x2+7x=6

3 (2/3) 2+7 (2/3) = 6

4/3+14/3=6

18/3=6

The x=2/3 is correct now lets see the x=-3

3x2+7x=6

3 (-3) 2+7 (-3) = 6

3 (9) - 21=6

27-21=6

6=6

so both x can be used in factoring