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7 March, 09:47

Find three consecutive natural numbers such that the difference of 5 times the third number and four times the first number is twice the second number

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  1. 7 March, 12:58
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    Theya re 1 apart

    n, n+1, n+2

    difference of 5 times (n+2) and 4 times n is 2 times (n+1)

    5 (n+2) - 4n=2 (n+1)

    distribute

    5n+10-4n=2n+2

    n+10=2n+2

    minus n both sides

    10=n+2

    minus 2 both sides

    8=n

    n+1=9

    n+2=10

    th enumbers are 8,9,10
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