what is 6 more than 7 times a number is 41

the problem would be set up as 6 + (7*x) = 41

first u take off the number 6 by subtracting it from itself to cancel it out then u do the same to the number 41

7x = 41 now u need to cancel out the number 7 attatched to the x so u divikde it by itself and then do the same to the other side so 41 divided by 7 = 5.9

so x = 5.9