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27 April, 10:33

In triangle ABC, a = 18.2, ∠B = 62°, and ∠C = 48°. Find b

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  1. 27 April, 11:28
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    To find angle a we do 180 - (62+48) = 180-110=70

    angle a = 70

    with this we can use the sin rule

    a/sin (A) = b/sin (B) = c/sin (C)

    since we have side a and angle A and angle b we can do:

    18.2/sin (70) = b/sin (62)

    then we can times by sin (62)

    (18.2/sin (70)) * sin (62) = 17.1
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