Solve the simultaneous equations: 5x - 3y = 12 2x - y = 5

5x - 3y = 12

2x - y = 5 so y = 2x - 5

5x - 3 (2x - 5) = 12

5x - 6x + 15 = 12

-x = 12 - 15

-x = - 3

x = 3

y = 2x - 5

y = 2 (3) - 5

y = 6 - 5

y = 1

solutions (3,1)

5x-3y=12

2x-y=5

I am going to use substitution method

2x-y=5 5x-3y=12 25/2-25/2-1/2=12-25/2

2x-y+y=5+y 5 (5/2+y/2) - 3y=12 - 1/2y=-1/2

2x/2=5/2+y/2 25/2+5y/2-3y=12 - 1/2y / - 1/2=-1/2 / - 1/2

x=5/2+y/2 25/2-1/2=12 y=1

Therefore y=1

5x-3y=12 5x-3 (1) = 12 5x-3=12 5x-3+3=12+3 5x = 15 5x/5=15/5 x=3

Therefore x=3 and y=1